There are two classification methods of triangles: by # of congruent sides (scalene = none, isosceles = 2, and equilateral = 3) AND by angle measures (acute = all under 90, right = 1 angle is 90, or obtuse = 1 is greater than 90). You need to look at classifying each triangle by both methods!
worksheet#2 problem 5 - how do you find x? I know that the side next to 122 is 58 and equals 180 but what about to solve for the x variable?
Yep you're on the right track. If you've already found 58, and you know the bottom right angle (what's that symbol mean again?)...can't you find the third angle of the triangle? HINT: the sum of all angles in a triangle always has to be _______.
Yep you're on the right track. If you've already found 58, and you know the bottom right angle (what's that symbol mean again?)...can't you find the third angle of the triangle? HINT: the sum of all angles in a triangle always has to be _______.
Dont understand how to do #14 (worksheet#2)
Okay, so you have a missing mark here...one of your class posted about this the night before this was due. You should have three sides marked congruent (two sides in the left triangle are visible, but the bottom side on the right-hand triangle didn't photocopy too well. See if that gives you a start. You'll need to find the missing angle measures first, then remember what you learned about the sides opposite base angles. Give it a go and see how it turns out.
Okay, so you have a missing mark here...one of your class posted about this the night before this was due. You should have three sides marked congruent (two sides in the left triangle are visible, but the bottom side on the right-hand triangle didn't photocopy too well. See if that gives you a start. You'll need to find the missing angle measures first, then remember what you learned about the sides opposite base angles. Give it a go and see how it turns out.
#20-21 on worksheet 2 why can't you use y2 - y1 over x2 - x1?
Because we're not asking you to find slope. We're asking if it's possible to make a triangle with those points. Well, you know how to determine if a triangle is possible if you are given the side lengths. The only difference here is that you're give the points, but not the lengths. That's why you need to find the length of the sides first (use the distance formula) and then the problems become just like 17-19 above.
Because we're not asking you to find slope. We're asking if it's possible to make a triangle with those points. Well, you know how to determine if a triangle is possible if you are given the side lengths. The only difference here is that you're give the points, but not the lengths. That's why you need to find the length of the sides first (use the distance formula) and then the problems become just like 17-19 above.
#25, #27, #30, #32 and #45 dont understand how to do
#25 and #27 are talking about SIMILAR triangles. Remember in similar triangles, the side lengths will be in the same proportions (ratios) in each triangle. So, in #25, the left side to the vertical side (written 25/18) must equal the left side to the vertical side in the right triangle as well (written 16/x). Set them equal to each other and solve for x. It's all about setting up proportions and solving for x.
#30 is a right triangle...you're given two sides and are asked to find the third. This one should be pretty straight forward from there!
#32...DRAW A PICTURE! In a square, if you draw in a diagonal, you've just formed two right triangles. Again, if you have two sides of the triangle, how do you find the third?
#45...DRAW A PICTURE!!! You are given the lengths of all three sides AND the perimeter of the triangle. Set up an equation, and solve for x. Give it a go and see how you do.
#30 is a right triangle...you're given two sides and are asked to find the third. This one should be pretty straight forward from there!
#32...DRAW A PICTURE! In a square, if you draw in a diagonal, you've just formed two right triangles. Again, if you have two sides of the triangle, how do you find the third?
#45...DRAW A PICTURE!!! You are given the lengths of all three sides AND the perimeter of the triangle. Set up an equation, and solve for x. Give it a go and see how you do.
--all from worksheet #2-- sorry if this is really long. Thank you!
Good questions...keep them coming, and don't forget about tutoring on Monday morning for any last-minute help!
Good questions...keep them coming, and don't forget about tutoring on Monday morning for any last-minute help!
Alright, everyone. I posted detailed comments to each of Caitlyn's questions. If you were stuck on one of the same questions, use those suggestions to get you started!
ReplyDelete