Questions for the quiz MONDAY

Hi Caitlyn,

I've posted replies to each of your questions below... 

Hey so for the review sheet for the quiz on monday,
For #7 on the answer key, why would it be negative 4 and not positive 4? You do 9 squared + b squared = 5 squared
Remember, your negative/positive indicates direction.  Any time you are moving left or down from the origin, it is a negative number to indicate direction.  Moving up or to the right would indicate a positive direction.
 
For #9, it says cot = -3. When you are labeling your triangle does it mater if its -3 and 1 or -1 and 3? I have my 3 sides as -3, 1, and square root of 10 so my answers are a little different from the answer key.
Remember your first step in any of these problems is to decide what quadrant you will be drawing your bow-tie angle in.  If cot is negative, and cos is positive, you know it has to be in quadrant IV.  Because we're moving to the Right, it has to be a positive 3.  Because we are moving Down, it has to be a negative 1.  Remember, you can always check your positive/negative chart (see the front of homework 4-2) for the signs of your final answers.

#10, Im having trouble finding what the numbers are for the sides of the triangle. I know its going to be in quadrant 2 but thats all I can figure out
Ok, so let's walk through this one.  You are right in that it is in Quadrant II.  That narrows it down to three angles (check your unit circle).  So how do we figure out which one it is?  Sec is the partner to cosine, so if the secent of theta is -2, then cosine is the reciprocal (-1/2).  Remember that cosine equates to your x-value, so which angle has an x-coordinate of -1/2?  That will identify your angle, and now you can use your knowledge of sin = y, cos = x, tan = y/x, and so on. 

#'s 11 and 12 I don't know how to go about solving them, they look very confusing
These two problems are just like we did on Friday in class (and similar to #10).  The only difference is it's telling you that your angle has to be somewhere between pi/2 (90 degrees) and 3pi/2 (270 degrees).  So where is there an angle whose cotangent is undefined (read: zero in the denominator) somewhere between 90 degrees and 270 degrees?  Remember cotangent is x/y!

#14, why would -4 be over 5? 5 is the hypotenuse and tangent is opposite over adjacent
Yes, you are right.  Tangent is opposite over adjacent.  So that gives you the 4/5.  But, it tells you it's in Quadrant IV, and in Quadrant IV, we know that tangent has to be negative!  Remember you need to be able to recreate that pos/neg chart from the front of homework 4-2.
 
and #'s 17-19 I need a short refresher on how to do those kinds of problems.
Ok, again these are just like the problems before, and the ones we did in class on Friday.  Use your unit circle to find an angle whose cotangent is 0.  Remember, cotangent is x/y, so if x/y = zero, that means you have zero in the numerator.  Where do you have angles who have zero as an x-coordinate?  There should be two!  You'll write the angles in degrees in the top blank, and in radians in the bottom blank.
 
THANKS!! :)
Hope that helps!

Studying?

How's the studying going for tomorrow's test?  Any questions can be posted here as a comment, and I'll get back to you as soon as I can!  Also, if you have the answer to someone else's question, feel free to post!

Quiz Grades

Quiz grades have been posted in the gradebook.  Have a look and see how you did.  All in all, they look pretty great!  I am very happy with the number of A's and B's in the class!  We will go over the review sheet in class on Wednesday, in preparation for Thursday's test. 

Way to go, and keep it up!

Review Sheet for Tuesday's Quiz

Good Sunday morning, Pre-Calculus classes!  The answer key to the Review Sheet has been uploaded to the Walton pre-calc blog at http://waltonhigh.typepad.com/precalc/.  Be sure to check your answers and if you have questions, post them HERE!!!  Tuesday's quiz will be 50% binomial expansion (make sure you review your homework!) and 50% combinations/permutations...have a great weekend!